原题目：https://leetcode-cn.com/problems/maximum-length-of-repeated-subarray/

 

思路：

滑动窗口法

代码：

class Solution {
public:
    int maxLength(vector<int>& A, vector<int>& B, int addA, int addB, int len) {
        int ret = 0, k = 0;
        for (int i = 0; i < len; i++) {
            if (A[addA + i] == B[addB + i]) {
                k++;
            } else {
                k = 0;
            }
            ret = max(ret, k);
        }
        return ret;
    }
    int findLength(vector<int>& A, vector<int>& B) {
        int n = A.size(), m = B.size();
        int ret = 0;
        for (int i = 0; i < n; i++) {
            int len = min(m, n - i);
            int maxlen = maxLength(A, B, i, 0, len);
            ret = max(ret, maxlen);
        }
        for (int i = 0; i < m; i++) {
            int len = min(n, m - i);
            int maxlen = maxLength(A, B, 0, i, len);
            ret = max(ret, maxlen);
        }
        return ret;
    }
};